Python Set MCQ

False

True True

{‘PYnative’, 1, (‘abc’, ‘xyz’)}

Set already has 1 as item True evaluates to 1. As you know set doesn’t allow duplicate element

{‘Pink’, ‘Blue’}

The difference() method returns a set that contains the difference between two sets.
Here set3 = set2.difference(set1) so the returned set contains items that exist only in the first set, and not in both sets.

sampleSet.discard("Orange")

The remove() and discard() method removes the specified item from a set.

True

{‘Blue’, ‘Orange’, ‘Yellow’, ‘Black’}

Python set doesn’t allow duplicate items.

{‘Yellow’, ‘Orange’, ‘Black’}

If the item to remove does not exist in the set, the discard() method will NOT raise an error. If we use remove() method to perform the same operation, we will receive a keyError.

{‘Yellow’, ‘Orange’, ‘Red’, ‘Black’, ‘Green’, ‘Blue’}

We can update multiple items using the update() method.

• We mostly use set for mathematical operations such as union and intersection.
• Sets are unordered; it means item order isn’t fixed. So we cannot be sure in which order the items will appear.
• The set is mutable. We can add or remove items from it when required.

True

TypeError

If you try to execute the above code you will get a TypeError: unhashable type: 'list'

• It is true that the set itself is changeable (mutable), but it cannot contain changeable objects such as list and dictionary.
• Python set can contain unchangeable objects like number, string, tuple etc

Syntax Error

We cannot access items in a set by referring to an index because the ‘set’ object does support indexing (the set is unordered). if you try to access items using the index, you will get TypeError: ‘set’ object does not support indexing.

Use a for loop to access set items.

sampleSet = {"Yellow", "Orange", "Black"}
for item in sampleSet:
  print(item)

When you set set2= set11, you are making them refer to the same dict object, so when you modify one of them, all references associated with that object reflect the current state of the object. So don’t use the assignment operator to copy the set instead use the copy() method or set() constructor.

True

Question was not answered

A = {30, 20, 10}
B = {50, 30, 40}
print(A.symmetric_difference(B))

{40, 10, 50, 20}

{‘Black’, ‘Yellow’}

The difference_update() method removes the items that exist in both sets. Here set1.difference_update(set2) removed the unwanted items from the original set1.

{40, 10, ’10’, 50, 20, 60, 30}

The union() method returns a new set with all items from both sets by removing duplicates