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int main() { int a = 4, n, i, result = 0; scanf("%d", n); for (i = 0;i < n; i++) result += a; }
void main() { int x = 1, y = 0, z = 5; int a = x && y && z++; printf("%d", z); }
#include void main() { int a = 5; int b = ++a + a++ + --a; printf("Value of b is %d", b); }
#include int main() { printf("%d >> %d %d >> %d\n", 4 >> 1, 8 >> 1); return 0; }
#include void main() { int x = 0; if (x = 0) printf("It's zero\n"); else printf("It's not zero\n"); }
#include void main() { char a = 'a'; int x = (a % 10)++; printf("%d\n", x); }
#include void main() { int a, b = 2, c; a = 2 * (b++); c = 2 * (++b); printf("a=%d, c=%d",a,c); }
Solution:b ^
a=a^bb=a^ba=a^b
Now 'a' will have 'b' s initial value and wise-versa.