Accept a character from the user and find it is a vowel or not without using any loop

C Programming Language / Decision Making of C Language

1097

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Program:

// Accept a character from the user and find it is a vowel or not without using any loop
#include <stdio.h>
int main()
{
    char c;
    int isLVowel, isUVowel;

    printf("Enter an alphabet: ");
    scanf("%c",&c);

    
    isLVowel = (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');

    
    isUVowel = (c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');

    
    if (isLVowel || isUVowel)
        printf("%c is a vowel.", c);
    else
        printf("%c is a consonant.", c);
    return 0;
}

Output:

Enter an alphabet: e
e is a vowel.
Press any key to continue . . .

Explanation:

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