Problems on Trains - General Knowledge Question and Answer

Problems on Trains - Question and Answer

This is aptitude questions and answers section on "Problems on Trains" with explanation for various interview, competitive examinations and entrance tests.

Which ministry launched the Talent Hunt for artists and give them a platform to showcase their talent on the national stage?

Minister of Environment and climate change
Ministry of culture and tourism
Ministry of Skill Development and Entrepreneurship
Ministry of Labour and Employment

Minister of culture and tourism Mahesh Sharma on Saturday launched the National Mission on Cultural Mapping of India in the city. Under the mission, the government will hold a "talent hunt" for artists of various genres and give them a platform to showcase their talent on the national stage. The artists can register themselves on the cultural mapping portal, after which they will be given a unique ID.

India's biggest municipal bonds programme was launched in _______________.

Odisha
Bihar
Maharasthra

Union Minister Venkaiah Naidu launched India's largest municipal bond program in Maharasthra after banging a gong to incorporate the Pune Municipal Corporation (PMC) in the list of BSE (Bombay Stock Exchange). The project looks to raise Rs 2,264 crore in five years. In its first part, the corporation raised Rs200 crore through the Bombay Stock Exchange's bond trading platform at a coupon rate (a fixed security amount) of 7.59% for 10 years.

The Homolographic projection has the correct representation of

shape
area
area
distance

No answer description available for this question.

120 metres
180 metres
324 metres
150 metres

option d

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

150 metres
324 metres
180 metres
120 metres

Speed = 60*(5/18) m/sec = 50/3 m/sec

Length of Train (Distance) = Speed * Time

(50/3) * 9 = 150 meter

A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

55 km/hr
54 km/hr
50 km/hr
45 km/hr

Relative speed = distance / time

The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

250 m
245 m
225 m
200 m

speed = (length of train + length of bridge) / time

1 : 3
3 : 2
3 : 4
None of these

Option B

300 m
240 m
120 m
None of these

Option B

89 sec
65 sec
100 sec
150 sec

Option A

72 m
80 m
82 m
50 m

Option D

42 sec
40 sec
45 sec
48 sec

Option B

36
45
48
49

Option C

72 sec
36 sec
18 sec
3.6 sec

Option B

20 sec
17.23 sec
12.86 sec
9.5 sec

Option C

100.1 m
223.1 m
111.1 m
120.3 m

111.1 m

5 sec
6 sec
7 sec
10 sec

Option B

9
10
9.6
10.8

Option D

30 km/hr
45 km/hr
60 km/hr
75 km/hr

Option C

240 m
260 m
320 m
230 m

Option D

230 m
240 m
270 m
260 m

Option C

24 km/hr
25km/hr
27km/hr
28km/hr

Option B

1 min 12sec
1min 24 sec
2min 24 sec
None of these

None of these

10 km/hr.
20 km/hr.
30 km/hr.
40 km/hr.

Option D

The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is:

400
525
750
850

Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.

Let the length of the train and that of the platform be x meters.

Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750

140 m
150 m
160 m
240 m

150 m

2.5 min
3.2 min
3.5 min
3 min

3 min

69.5 km/hr
70 km/hr
79 km/hr
79.2 km/hr

50 m
150 m
200 m

130
360
500
540

320 m
350 m
650 m

A train traveling at a speed of 30m/sec crosses a platform 600m long in 30seconds. The length of the train is

120m
150m
200m
300m

Let the length of the train be x m.

Then it’s Speed = = 30 => 600 + x = 900 => x = 300m

200m
225m
245m
250m

A train traveling at constant speed crosses a 96m long platform in 12 seconds and another 141m long platform in 15 seconds. The length of the train and it’s speed are?

64m. 44km/hr
64m.54km/hr
84m.54km/hr
84m.60km/hr

The answer is the option C

A train crosses a pole in 15 seconds while it crosses a 100m long platform in 25 seconds. The length of the train is

125m
135m
150m
175m

The answer is the Option C

Two trains 105m and 90m long run at the speeds of 45 kmph and 72 kmph respectively in opposite direction on parallel tracks. The time which they take to cross each other is

5 sec
6 sec
7 sec
8 sec

Sum of the lengths of the trains = (105 + 90)m = 195m

Relative speed = (72 +45)kmph

= 117kmph =(117 x 5/18)m/sec = 585/18 m/sec

Required Time = (195 x 18/585)sec = 6 Sec

How many seconds will a 500-meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?

25
30
40
45

The Option B is the correct answer

A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

48 km/hr
54 km/hr
66 km/hr
82 km/hr

82 km/hr is the correct answer

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 meters, in what time (in seconds) will they cross each other traveling in opposite direction?

10
12
15
20

Option B is the correct answer

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.

12 sec
24 sec
48 sec
60 sec

Option B is the correct answer

Two trains are running in opposite directions with the same speed. If the length of each train is 120 meters and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:

10
18
36
72

Option C is the correct answer

Two stations A and B are 110 kms apart on a straight line. One train starts from A at 7 a.m and travels towards B at 20km per hour speed Another train starts from B at 8 a.m. and travels towards A at a speed of 25 Km per hour at what time will they meet?

9 a.m
10 a.m
11 a.m
none of these

Suppose they meet x hrs after 7 a.m

Distance covered by A in x hrs = (20 × x)

Distance covered by B in (x-1) hrs = 25 (x -1) km.

So they meet at 10 a.m.

A train running at certain speed crosses a stationary engine in 20 seconds. To find out the speed of the train. Which of the following information is necessary:

Only the length of the train
Only the length of the engine
Either the length of the train of the length of the engine
Both the length of the train and the length of the engine.

Since the sum of the lengths of the train and the length of the engine is needed, So both the lengths must be known.

A 120m long train takes 10 seconds to cross a man standing on a platform. The speed of the train is

10m/sec
12 m/sec
15 m/sec
20 m/sec

Speed = (120/10) m/sec = 12 m/sec

The speed of a train 150m long is 50kmph. How much time will it take to pass a platform 600m long?

50 sec
54 sec
60 sec
64 sec

Speed =(50 x 5/18) m/sec = 125/9 m/sec

Required Time = 54 sec

How much time will a train 171m long take to cross a bridge 229m long, if it is running at a speed of 45kmph?

40 sec
35 sec
32 sec
30 sec

Speed = 25/2 m/sec

Required time = 32 sec

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?

23 m
29 m
250/9 m
240/9 m

Option C is the correct answer

A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is

400 m
450 m
560 m

Option A is the correct answer

A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?

66 km/hr
72 km/hr
78 km/hr
81 km/hr

Option D is the correct answer

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:

45 m
50 m
54 m
72 m

Option B is the correct answer

A train crosses a platform 100 meters long in 60 seconds at a speed of 45 km per hour. The time taken by the train to cross an electric pole, is:

8 Seconds
1 minute
52 Seconds

Length of train = x meters

Speed = (45 × 5/18) m/sec = (25/2) m/sec

Distance covered in crossing the platform = (x + 100) m

(x + 100) × 2/25 = 60

or 2x + 200 = 1500 or x = 650

Time is taken to cross the pale

= (650 × 2/25) Sec = 52 Sec.

A train of length 150 meters takes 10 seconds to pass over another train 100 meters long coming from the opposite direction. If the speed of the first train be 30 kmph. The speed of the second train is:

54 kmph
60 kmph
72 kmph
36 kmph

Relative speed = (150+100│10) m/sec = 25 m/sec

Speed of second train = (90-30) km/hr = 60 km/hr

A 150-meter long train crosses a man walking at the speed of 6 kmph in the opposite direction in 6 seconds. The speed of the train in km/hr is:

66
84
96
106

Speed of the train be x km/hr

Relative speed = (x + 6) km/hr

= [(x+6)×5/18] m/sec = 150/6

= ((x+6)×5)/18

or 5x + 30 = 450

or x = 84 km/hr

A train speeds past a pale in 15 seconds and speeds past a platform 100 meters long in 25 seconds. Its length in meters is:

200
150
50

length of the train be x meters and its

speed be y meters/sec x/y = 15

=> y = x/15

=> (x+100)/25 = x/15

=> x = 150 m

A train 100 meters long moving at a speed of 50 kmph crosses a train 120 meters long coming from opposite direction in 6 seconds. The speed of second train is:

132 kmph
82 kmph
60 kmph
50 kmph

Speed of the second train be x km/hr.

Relative speed = (50 + x) km/hr

= [(50 + x) × 5/18] m/sec

= (250+5x│18) m/sec 220 × 18

= 6 (250 + 5 x)

The speed of the second train = 82 km/hr.

Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:

2 : 3
4 : 3
6 : 7
9 : 16

Option B is the correct answer

A train 50 meters long passes a platform 100 meters long in 10 seconds. The speed of the train is:

10 km/hr
15 km/hr
54 km/hr
100 km/hr

Distance covered by train in 10 sec = (50+100)m = 150m

Speed = (150/10)m/sec = (15 ×18/5) km/hr = 54 km/hr

A person sees a train passing over 1 km long bridge. The length of the train is half that of the bridge if the train clears the bridge in 2 minutes the speed of the train is:

50 km/hr
45 km/hr
60 km/hr
30 km/hr

Distance covered in 2/60 hr = (1+1/2) km = 3/2 km.

Distance covered in 1 hr = (3/2 × 60/2) km = 45 km.

Speed of the train = 45 km/hr

A train 700 m long is running at the speed of 72km per hour if it crosses a tunnel in 1 minute. Then the length of the tunnel is:

500m
550m
600m
700m

Speed = (72 × 5/18 ) m/sec = 20 m/sec

Length of tunnel = x meters

(700+x)/60 = 20

=> 700 + x = 1200 or x = 500 m

A train 270 meters long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in:

36 Seconds
32 Seconds
28 Seconds
24 Seconds

Relative speed = (25+2) km/hr

= 27 km/hr

= (27 x 5/18) m/sec

= (15/2) m/sec.

Time taken by the train to pass the man.

= (270 × 2/15) Sec = 36 Sec.

A train 300 m long crossed a platform 900 m long in 1 minute 12 seconds. The speed of the train in km/hr was:

45
50
54
60

Distance covered in 72 sec = (300+900)m

Speed = (1200/72)m/sec

=(50/3) m/sec

= (50/3 × 18/5) km/hr = 60 km/hr.

A train moves with the speed of 180 km.hr then its speed in meters per second is:

5
30
40
50

180 km/hr = (180 × 5/18)m/sec = 50 m/sec

A train 280 meters long is moving at speed of 60 km/hr. The time taken by the train to cross a platform 220 meters long is:

20 Seconds
25 Seconds
30 Seconds
35 Seconds

Speed of the train = (60 × 5/18) m/sec = (50/3) m/sec.

Time taken by the train to cross the platform

=Time taken by it to cover (280+220)m

=(500 × 3/50) sec = 30 sec.

Two goods train every 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?

12 sec
24 sec
48 sec
60 sec

Relative speed = 45 + 30 = 75 km/hr.

75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.

Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?

50 m
72 m
80 m
82 m

Let the length of each train be x m.

Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.

A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?

230 m
240 m
260 m
320 m

Relative speed = 120 + 80 = 200 km/hr.

= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.

A train 110 m long is running at a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?

5 sec
6 sec
7 sec
10 sec

Speed of train relative to man = 60 + 6 = 66 km/hr.

= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.

A jogger running at 9 km/hr alongside a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?

3.6 sec
18 sec
36 sec
72 sec

Speed of train relative to jogger = 45 - 9 = 36 km/hr.

= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.

A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?

320 m
350 m
650 m
None of these

Speed = 300/18 = 50/3 m/sec.

Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.

A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?

90 m
100 m
120 m
140 m

Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.

Length of the train = 20 * 6 = 120 m.

In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?

2.5 sec
4.25 sec
5 sec
12.5 sec

Speed = 144 * 5/18 = 40 m/sec

Time taken = 100/40 = 2.5 sec.

A train 280 m long, running with a speed of 63 km/hr will pass a tree in?

15 sec
16 sec
18 sec
20 sec

Speed = 63 * 5/18 = 35/2 m/sec

Time taken = 280 * 2/35 = 16 sec

How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?

9.8 sec
12.1 sec
12.42 sec
14.3 sec

Speed = 72 * 5/18 = 20 m/sec

Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.

A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?

180 sec
190 sec
170 sec
175 sec

L = S*T

S= 1200/120

S= 10 m/Sec.

Total length (D)= 1900 m

T = D/S

T = 1900/10

T = 190 Sec

A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?

20 sec
30 sec
40 sec
50 sec

Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec

Total distance = 360+140 = 500 meter

Time = Distance/speed

= 500 * (2/25) = 40 seconds

A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?

175 m
180 m
185 m
170 m

Length of the train be ‘X’

X + 120/15 = X + 180/18

6X + 720 = 5X + 900

X = 180m

A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?

150 m
165 m
155 m
160 m

Length of the train be ‘X’

X + 150/15 = X + 250/20

4X + 600 = 3X + 750

X = 150m

A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?

65 Kmph
70 Kmph
72 Kmph
75 Kmph

Length = Speed * time

Speed = L/T

S = 400/20

S = 20 M/Sec

Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)

Speed = 72 Kmph

The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?

58 Kmph
68 Kmph
78 Kmph
55 Kmph

Length of the two trains = 600m + 400m

Speed of the first train = X

Speed of the second train= 48 Kmph

1000/X - 48 = 180

1000/x - 48 * 5/18 = 180

50 = 9X - 120

X = 68 Kmph

A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?

150 m
200 m
350 m
400 m

Speed = [300 / 18] m/sec = 50/3 m/sec.

Let the length of the platform be x meters.

Then, x + 300 / 39 = 50/3

3(x + 300) = 1950 è x = 350m.