What is method overloading in C#?
C# Programming Language > OOPS Concept > Introduction to OOP Concept
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Answer:
Method overloading is mechanism to create multiple methods with the same name and unique signature in the same class. When you go for compilation, the compiler uses overload resolution to determine the specific method to be invoked.
With method overloading, multiple methods can have the same name with different parameters:
Example
int MyMethod(int x) float MyMethod(float x) double MyMethod(double x, double y)
Consider the following example, which have two methods that add numbers of different type:
Example
using System;
namespace MyApplication
{
class Program
{
static int PlusMethodInt(int x, int y)
{
return x + y;
}
static double PlusMethodDouble(double x, double y)
{
return x + y;
}
static void Main(string[] args)
{
int myNum1 = PlusMethodInt(8, 5);
double myNum2 = PlusMethodDouble(4.3, 6.26);
Console.WriteLine("Int: " + myNum1);
Console.WriteLine("Double: " + myNum2);
}
}
}
Output
Int: 13 Double: 10.559999999999999
Instead of defining two methods that should do the same thing, it is better to overload one. In the example below, we overload the PlusMethod method to work for both int and double:
Example
using System;
namespace MyApplication
{
class Program
{
static int PlusMethod(int x, int y)
{
return x + y;
}
static double PlusMethod(double x, double y)
{
return x + y;
}
static void Main(string[] args)
{
int myNum1 = PlusMethod(8, 5);
double myNum2 = PlusMethod(4.3, 6.26);
Console.WriteLine("Int: " + myNum1);
Console.WriteLine("Double: " + myNum2);
}
}
}
Output
Int: 13 Double: 10.559999999999999
Note: Multiple methods can have the same name as long as the number and/or type of parameters are different.
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