C program to print circle box number pattern with 1 and 0 
01110
10001
10001
10001
01110

C Programming Language / Loop control in C Language

2871

Program:

/**
 * C program to print circle box number pattern
* www.atnyla.com
 */

#include <stdio.h>

int main()
{
    int i, j, rows, cols;

    /* Input rows and columns from user */
    printf("Enter rows: ");
    scanf("%d", &rows);
    printf("Enter columns: ");
    scanf("%d", &cols);

    for(i=1; i<=rows; i++)
    {
        for(j=1; j<=cols; j++)
        {
            // Print corner element
            if((i==1 || i==rows) && (j==1 || j==cols))
            {
                printf("0");
            }
            else if(i==1 || i==rows || j==1 || j==cols)
            {
                // Print edge
                printf("1");
            }
            else
            {
                // Print center
                printf("0");
            }
        }

        printf("\n");
    }

    return 0;
}

Output:

Enter rows: 5
Enter columns: 5
01110
10001
10001
10001
01110

Explanation:

Required knowledge

Basic C programming, Loop

Logic to print circle box number pattern

The given pattern is almost similar to one of previous explained pattern -

 

11111
10001
10001
10001
11111

 

The only difference is zero gets printed for corner elements instead of 1.
Below is the step by step descriptive logic to print the given pattern.

  1. Input number of rows and columns to print from user. Store it in some variable say rows and cols.
  2. To iterate through rows run an outer loop from 1 to rows. The loop structure should look like for(i=1; i<=rows; i++).
  3. To iterate though columns run an inner loop from 1 to cols. The loop structure should look like for(j=1; j<=cols; j++).
  4. Inside the inner loop, print 1 for edges except for corner elements. Which is if(i==1 || i==rows || j==1 || j==rows) and not a corner then print 1 otherwise print 0.
  5. Finally, move to the next line after printing all columns of a row.

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