Program to print the given number pattern
1
22
333
4444
55555
C Programming Language / Loop control in C Language
25084Program:
/** * C program to print number pattern * www.atnyla.com */ #include <stdio.h> int main() { int i, j, N; printf("Enter N: "); scanf("%d", &N); for(i=1; i<=N; i++) { for(j=1; j<=i; j++) { printf("%d", i); } printf("\n"); } return 0; }
Output:
1 22 333 4444 55555
Explanation:
Required knowledge
Basic C programming, Loop
Logic to print the given number pattern 1
If you are following my previous posts then you might notice that these two patterns are similar to one of the previous number pattern that I have discussed earlier. Hence, it is recommended to go through it as it will help you to build logic for the pattern we are going to print.
11111 22222 33333 44444 55555
Now considering the first pattern that we need to print.
1 22 333 4444 55555
If you notice, in above pattern if we start from 1st to 5th row, the current row number gets printed in every columns. Also number of columns per row is dependent on the current row number (i.e. there are 1 columns in row1, 2 in row2, 3 in row3 and so on). So lets, write down step by step logic to the above pattern.
- To iterate through rows, initialize an outer loop from 1 to N (where N is the total rows to be printed).
- To print columns per row, initialize an inner loop from 1 to current_row_number (since columns are row dependent). Inside this loop print the value of current_row_number.
And you are done. Lets write down its code.
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