Program to print the given number pattern 
54321
 5432
  543
   54
    5

C Programming Language / Loop control in C Language

5023

Program:

/**
 * C program to print number pattern
 */

#include <stdio.h>

int main()
{
    int i, j, N;

    printf("Enter N: ");
    scanf("%d", &N);

    for(i=1; i<=N; i++)
    {
        // Logic to print spaces
        for(j=1; j<i; j++)
        {
            printf(" ");
        }

        // Logic to print numbers
        for(j=N; j>=i; j--)
        {
            printf("%d", j);
        }

        printf("\n");
    }

    return 0;
}

Output:

54321
 5432
  543
   54
    5

Explanation:

Logic to print the given number pattern

 

54321
 5432
  543
   54
    5

 

Once you get done with the first number pattern, then this wouldn't be much difficult as it is same as the pattern we just did except of trailing spaces. We only need to add the logic of printing spaces just before the number gets printed. If you hover mouse to the pattern above you can see or count total number of spaces per row and can easily think about the logic to print spaces. Here spaces are arranged in ascending order fashion i.e. first row contains 0 spaces, second row contains 1 space and so on last row contains 4 space. Total number of spaces per row is i - 1 (where i is the current row number).
Step-by-step descriptive logic to print spaces:

  1. To print space, run an inner loop from 1 to i - 1. Inside this loop print single blank space.

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