DATEDIFF() Function in SQL Server
Table of Content:
Syntax:
DATEDIFF(datepart, startdate, enddate)
DATEDIFF(datepart, startdate, enddate) - Returns the count of the specified datepart boundaries crossed between the specified startdate and enddate.
DatePart | Abbreviations |
---|---|
year | yy, yyyy |
quarter | qq, q |
month | mm, m |
dayofyear | dy, y |
day | dd, d |
week | wk, ww |
weekday | dw |
hour | hh |
minute | mi, n |
second | ss, s |
millisecond | ms |
microsecond | mcs |
nanosecond | ns |
TZoffset | tz |
ISO_WEEK | isowk, isoww |
Code:
Select DATEDIFF(MONTH, '11/30/2005','01/31/2006') Select DATEDIFF(DAY, '11/30/2005','01/31/2006')
Output:
The above code will produce the following result-
2 62